| Date | From | To | Departure | Arrival | Status | |
|---|---|---|---|---|---|---|
| May 29 | LRD | BMI | 06:34 | 09:25 |
Landed
|
Track > |
EZ Air Flight 7Z758 connects Laredo, United States to Bloomington, United States, taking off from Laredo International Airport LRD and landing at Bloomington Central Illinois Regional Airport BMI.
How long is the 7Z758 flight from Laredo to Bloomington?
The average flight time from Laredo to Bloomington is 2 hours and 51 minutes. The flight distance is 1733 km / 1077 miles and the average flight speed is 608 km/h / 378 mph.
How many 7Z758 flights are operated per week?
1 flight per week. The flight 7Z758 is operated on Friday.
What is the On-Time Performance (OTP) of EZ Air Flight 7Z758 Laredo to Bloomington?
The Airportia On-Time Performance Rating for EZ Air Flight 7Z758 is 5/5 stars. This metric is calculated using data from the past 10 flights.
When was the latest 7Z758 flight?
The latest flight took off on Friday, May 29th, 2026 with the flight status being Landed on 09:25.
How else can the flight 7Z758 be referenced as?
This EZ Air flight can also be referenced as EZR758, 7Z0758, 7Z 758, EZR 758.
How often is flight 7Z758 delayed?
On average, 100% of all 7Z758 flights are delayed. The average delay is 1 minute.
See our 7Z758 Flight Tracker above for more details.
Other flights departing from Laredo LRD: IF841, AA3372, UA4226, A87149
Other flights arriving at Bloomington BMI: G4996, DL4952, AA3436, A87149
All flights connecting Laredo LRD to Bloomington BMI.