| Date | From | To | Departure | Arrival | Status | |
|---|---|---|---|---|---|---|
| Jun 11 | JAX | AEX | 14:09 | 14:44 |
En-Route
|
Track > |
American Airlines Flight AA7455 connects Jacksonville, United States to Alexandria, United States, taking off from Jacksonville International Airport JAX and landing at Alexandria International Airport AEX.
How long is the AA7455 flight from Jacksonville to Alexandria?
The average flight time from Jacksonville to Alexandria is 1 hour and 35 minutes. The flight distance is 1040 km / 646 miles and the average flight speed is 657 km/h / 408 mph.
What is the On-Time Performance (OTP) of American Airlines Flight AA7455 Jacksonville to Alexandria?
The Airportia On-Time Performance Rating for American Airlines Flight AA7455 is 5/5 stars. This metric is calculated using data from the past 10 flights.
When was the latest AA7455 flight?
The latest flight took off on Thursday, June 11th, 2026 with the flight status being En-Route on 14:44.
How else can the flight AA7455 be referenced as?
This American Airlines flight can also be referenced as AAL7455, AA 7455, AAL 7455.
How often is flight AA7455 delayed?
On average, 0% of all AA7455 flights are delayed. The average delay is 0 minutes.
Can I get compensation for my delayed or cancelled AA7455 flight or baggage issues?
If your AA7455 flight was cancelled, delayed, or if you experienced baggage issues such as delayed, damaged, or lost bags, you may be entitled to compensation. Compensation amounts and eligibility depend on various regulations, including EC 261/2004, UK261, CA Montreal Convention, US GoodWill, BR-ANAC, SA-GACA and TK-SHY.
See our AA7455 Flight Tracker above for more details.
Other flights departing from Jacksonville JAX: AA2001, AA4561, G41535, WN2158
Other flights arriving at Alexandria AEX: DL4991, UA5044, DL5314, OY2272
All flights connecting Jacksonville JAX to Alexandria AEX.