How long is the VS4808 flight from Cleveland to New York?

Virgin Atlantic Airways' Cleveland–New York flight covers 683 km (424 mi) and runs once a week, on Fridays. The timetable allows 7 h 41 min; there is not enough recent history yet to say how long it usually takes. Yesterday's flight was scheduled to leave at 18:47, but its status has not been confirmed.

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About VS 4808

Virgin Atlantic Airways Flight VS4808 connects Cleveland, United States to New York, United States, taking off from Cleveland Hopkins International Airport CLE and landing at New York John F. Kennedy International Airport JFK.

Route: Cleveland Hopkins International Airport CLE to New York John F. Kennedy International Airport JFK
Distance: 683 km (424 mi)
Scheduled flight time: 7 h 41 min
Flies: Fri

VS 4808 FAQ

How long is the VS4808 flight from Cleveland to New York?: The timetable allows 7 h 41 min. Cleveland to New York is 683 km (424 mi).
Which days does VS4808 fly from Cleveland to New York?: Once a week, on Fridays, based on the schedule of the last 7 days.
What other flight numbers does VS4808 have?: Also listed as VIR4808 (Virgin Atlantic Airways' ICAO code) and VS 4808.

VS4808 and Cleveland CLE to New York JFK Flights

Flight VS4808 is a code-share Virgin Atlantic Airways flight of the Delta Air Lines operated DL951.

Other flights departing from Cleveland CLE: WN1806, UA67, DL951

Other flights arriving at New York JFK: AV7394, CM808, DL951

All flights connecting Cleveland CLE to New York JFK.